Problem19: VAD

¡Puedes leer este texto en español! Problema19: VAD

Ej19. The number of surface defects of the plastic panels used inside the car, follows a Poisson distribution with value mean equal to 0.5 defects per square meter of panel.

If the inside the car has 4 square meter of this material then, which is the probability that there won't be any surface defects?.


We conduct a data compilation given by problem statement:

· X ≡ 'Number of surface defects of the plastic panels that are used inside the car'.
· The random variable X follows a Poisson distribution: X ~ P(0.5).

If a car has 4 m² of this material, we have to adapt the variable for this specification:

· Random variable X with 4 m²: X ~ P(4·0.5) = P(2).

We must get the following probability:

Finally, the probability that there won't be any surface defect of the plastic panels inside the car with 4 m² of this material is 0.135335.